7 / 5x + 2 ifadesi sadeleştirilebilir bir kesir olduğuna göre, x´in bir basamaklı kaç doğal sayı değeri vardır?
2/3´sinin 2 eksiği, yarısından 5 fazla olan sayı kaçtır?
7 / 5x + 2 ifadesi sadeleştirilebilir bir kesir olduğuna göre
since this statement (7 / 5x + 2 ) is a fraction that can be simplificated,
x´in bir basamaklı kaç doğal sayı değeri vardır?
how many of one digit natural numbers has "x" ?
2/3´sinin 2 eksiği, yarısından 5 fazla olan sayı kaçtır?
what is the number that is 2 less than its 2/3 is 5 more than its half ?
7
---- As 1,2,3,4,5,6,7,8,9 are one digit natural numbers
5x+2 "0" is natural number but we cant put "0" ..5.0+2 = would be undefinable.
5.1+2 BUT we can take only one of them 5.1+2 = 7 cos this way this fraction can
5.2+2 be simplificated. 7 7
5.3+2 ---- = ---- = 1 so the answer is Only one natural number
5.4+2 5.1+2 7 "X" can take.
5.5+2
5.6+2
5.7+2
5.8+2
5.9+2
my math wasnt great at school but this is my try..)
When it comes to the second one:
2/3´sinin 2 eksiği, yarısından 5 fazla olan sayı kaçtır?
what is the number that is 2 less than its 2/3 is 5 more than its half ?
2x 1x 2x 1x
---- - 2 = ----- + 5 ===========> ------ - ------ = 5+2
3 2 3 2
(2) (3)
4x 3x x 7
----- - ---- = 7 ==============> ---- = ---- ===> x = 6.7 = 42
6 6 6 1
so the answer for the second problem is 42 I am hundred percent sure about this one.
Edited (3/10/2011) by tunci
Edited (3/10/2011) by tunci
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